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Quantitative Aptitude

Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.

1) Two stations A and B are 310 km apart on a straight line. One train starts from A at 10 a.m. and travels towards B at 40 km/hr. Another train starts from B at 11 a.m. and travels towards A at a speed of 50 km/hr. At what time will they meet?

A.3 pm

B.1 pm

C.2 pm

D.4 pm

E.None of these

2) A train crosses a 450 m long platform in 28 seconds and the same train crosses a man standing in a platform in 10 seconds. What is the time taken by the same train crosses 200m tunnel?

A.12 seconds

B.15 seconds

C.16 seconds

D.18 seconds

E.None of these

3) Two trains A and B running in opposite direction at the speed of 60 kmph and 72 kmph respectively. Length of train A and B is 300 m and 360 m respectively. In how much time will they take to cross each other?

A.24 seconds

B.18 seconds

C.12 seconds

D.36 seconds

E.None of these

4) Train A crosses the tunnel which is double the length of train A in 18 seconds and train A crosses a 200m long train B running in opposite direction at the speed of 60 kmph in 9 seconds. Find the length of the tunnel?

A.100 m

B.200 m

C.180 m

D.300 m

E.None of these

5) The speed of two trains is in the ratio of 8: 5. They are moving in opposite directions along the parallel tracks. If each takes 6 seconds to cross a pole, find the time taken by the train to cross each other completely.

A.2 seconds

B.4 seconds

C.6 seconds

D.8 seconds

E.None of these

Answers :

1) Answer: C

They meet x hours after 10 a.m.

Distance covered by A in x hours = 40x km

Distance covered by B in (x – 1) hours = 50 * (x – 1) km

40x + 50 * (x – 1) = 310

40x + 50x – 50 = 310

9x = 360

x = 4

They meet at 2 p.m.

2) Answer: D

Length of the train = x

Speed of train = y

450 + x = y * 5/18 * 28

4050 + 9x = 70y

x = y * 5/18 * 10

9x = 25y

4050 + 25y = 70y

y = 90 kmph

x = 250 m

Required time = [(250 + 200)/90] * 18/5 = 18 seconds

3) Answer: B

Required time = (300 + 360)/((60 + 72) * 5/18)

= 18 seconds

4) Answer: B

Length of train A = x

Length of Tunnel = 2x

Speed of train A = y

x + 2x = y * 5/18 * 18

3x = 5y

x+ 200 = (y + 60) * 5/18 * 9

2x + 400 = 5y + 300

2x + 400 = 3x + 300

x = 100

Length of tunnel = 2 * 100 = 200 m

5) Answer: C

Time taken by the trains to cross each other = (t1 * x + t2 * y)/(x + y)

= (6 * 8 + 6 * 5)/(8 + 5)

= (48 + 30)/13

= 6 seconds