Quantitative Aptitude
Aug 11 2022
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
1) Two stations A and B are 310 km apart on a straight line. One train starts from A at 10 a.m. and travels towards B at 40 km/hr. Another train starts from B at 11 a.m. and travels towards A at a speed of 50 km/hr. At what time will they meet?
A.3 pm
B.1 pm
C.2 pm
D.4 pm
E.None of these
2) A train crosses a 450 m long platform in 28 seconds and the same train crosses a man standing in a platform in 10 seconds. What is the time taken by the same train crosses 200m tunnel?
A.12 seconds
B.15 seconds
C.16 seconds
D.18 seconds
E.None of these
3) Two trains A and B running in opposite direction at the speed of 60 kmph and 72 kmph respectively. Length of train A and B is 300 m and 360 m respectively. In how much time will they take to cross each other?
A.24 seconds
B.18 seconds
C.12 seconds
D.36 seconds
E.None of these
4) Train A crosses the tunnel which is double the length of train A in 18 seconds and train A crosses a 200m long train B running in opposite direction at the speed of 60 kmph in 9 seconds. Find the length of the tunnel?
A.100 m
B.200 m
C.180 m
D.300 m
E.None of these
5) The speed of two trains is in the ratio of 8: 5. They are moving in opposite directions along the parallel tracks. If each takes 6 seconds to cross a pole, find the time taken by the train to cross each other completely.
A.2 seconds
B.4 seconds
C.6 seconds
D.8 seconds
E.None of these
Answers :
1) Answer: C
They meet x hours after 10 a.m.
Distance covered by A in x hours = 40x km
Distance covered by B in (x – 1) hours = 50 * (x – 1) km
40x + 50 * (x – 1) = 310
40x + 50x – 50 = 310
9x = 360
x = 4
They meet at 2 p.m.
2) Answer: D
Length of the train = x
Speed of train = y
450 + x = y * 5/18 * 28
4050 + 9x = 70y
x = y * 5/18 * 10
9x = 25y
4050 + 25y = 70y
y = 90 kmph
x = 250 m
Required time = [(250 + 200)/90] * 18/5 = 18 seconds
3) Answer: B
Required time = (300 + 360)/((60 + 72) * 5/18)
= 18 seconds
4) Answer: B
Length of train A = x
Length of Tunnel = 2x
Speed of train A = y
x + 2x = y * 5/18 * 18
3x = 5y
x+ 200 = (y + 60) * 5/18 * 9
2x + 400 = 5y + 300
2x + 400 = 3x + 300
x = 100
Length of tunnel = 2 * 100 = 200 m
5) Answer: C
Time taken by the trains to cross each other = (t1 * x + t2 * y)/(x + y)
= (6 * 8 + 6 * 5)/(8 + 5)
= (48 + 30)/13
= 6 seconds