# Quantitative Aptitude

Aug 26 2023

Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.

**What is the approximate value should come in place of question mark in the following questions?**

**1) 8.99 ^{2} -? = 5.01^{2} + 3.009^{2}**

**A**.27

**B**.37

**C**.47

**D**.57

**E**.50

**2) (43.98+16.01) ÷ 2.03 × 4.99 = ? ^{2} + 50.03**

**A**.20

**B**.10

**C**.25

**D**.30

**E**.15

**3) ³√(27.003) of 9.98 ^{2} ÷ 5.99 = 8.003^{2}- ?**

**A**.20

**B**.10

**C**.14

**D**.18

**E**.none of these

**4) (2 ÷ 3.98) of 29.978 +? ÷ 4.99 = 30.01 – 3.02 ^{2}**

**A**.24

**B**.35

**C**.20

**D**.30

**E**.none of these

**5) 2.003 + 5.006 – 12.9998 + 30.979 – 10.005 = ?**

**A**.10

**B**.09

**C**.11

**D**.12

**E**.15

**Answers :**

**1) Answer: C**

8.99^{2} - x = 5.01^{2} + 3.009^{2}

9^{2 }– x = 5^{2} + 3^{2}

81 – x = 25 + 9

x = 47

**2) Answer: B**

(43.98+16.01) ÷ 2.03 × 4.99 = x^{2} + 50.03

(44+16) ÷ 2 × 5 = x^{2} + 50

x^{2} +50 = 60 ÷ 2×5

x^{2} + 50 = 30×5

x^{2} = 150-50

x = 10

**3) Answer: C**

³√(27.003) of 9.98^{2} ÷ 5.99 = 8.003^{2} - x

3 of 100 ÷ 6 = 64 –x

x= 64-50

x = 14

**4) Answer: D**

**(2 ÷ 3.98) of 29.978 +? ÷ 4.99 = 30.01 – 3.02 ^{2}**

(2÷4) of 30 + x ÷ 5 = 30 - 3^{2}

1/2 of 30 + x ÷ 5 = 30 – 9

15 + x ÷ 5 = 21

x ÷5 = 6

x = 6×5 =30

**5) Answer: E**

2.003 + 5.006 – 12.9998 + 30.979 – 10.005 = x

x = 2 + 5 – 13 +31 – 10

x = 38 – 23

x = 15