Payment Processing...

Quantitative Aptitude DI

Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.

Read the data given below in the paragraph carefully and answer the questions given below:

Ravish manufactured an item for which he required raw material, labour and transportation. Cost of raw material is Rs.14400 and cost of labour is ___(A)____rupees. Cost of transportation is Rs.17400 and marked up that item by 60% over its manufacturing cost which is Rs.27000. He sold the item after allowing two successive discounts 25% and ___(B)___ percent respectively and gains Rs.900. Total amount of discount given by him is ____(C)____rupees and the amount that Ravish received after selling the item, he invested in a scheme for ____(D)____ years at 20% annual CI. Total amount of interest received by him from the scheme is Rs.20196. Now, Ravish and Manish started doing a work and together they can do the work in B days. If Ravish is 60% as efficient as Manish and difference between time taken by Ravish and Manish alone to do the work is ____(E)____ days.

1) Value of A?

a) 14400

b) 13200

c) 12400

d) 11600

e) 19200

2) Value of B?

a) 25

b) 10

c) 5

d) 20

e) 15

3) Value of C?

a) 23400

b) 27200

c) 26100

d) 25200

e) 29100

4) Value of D?

a) 1.5

b) 3

c) 1

d) 2

e) 2.5

5) Value of E?

a) 16

b) 24

c) 20

d) 18

e) 12

Answers :

1) Answer: B

Total manufacturing cost of item = 14400 + A + 17400 = (31800 + A)

Marked up amount on the item = 60% of (31800 + A) = 27000

19080 + 0.6A = 27000

A = 13200

2) Answer: E

Selling price of item = (100 – B)% of 75% of 160% of (31800 + A) = (31800 + A) + 900

(100 – B) * (38160 + 1.2A) = 100(32700 + A)

(100 – B) * 54 = 4590

100 – B = 85

B = 15

3) Answer: C

Amount received by Ravish after selling the item = (31800 + A) + 900 = Rs.45900

Marked price of item = (31800 + A) + 27000 = Rs.72000

Total amount of discount = C = 72000 – 45900

C = 26100

4) Answer: D

According to the question:

45900 * (112/100) D = 45900 + 20196

45900 * (1.2) D = 45900 + 20196

1.2D = 66096/45900 = 1.44

1.2D = 1.22

D = 2

5) Answer: A

Ratio of efficiency of Ravish to Manish = 60: 100

Ratio of efficiency of Ravish to Manish = 3: 5

Let time taken by Ravish and Manish alone to do the work is ‘5x’ and ‘3x’ respectively.

Now,

(1/5x) + (1/3x) = (1/B)

(3 + 5)/15x = (1/15)

8/x = 1

x = 8

Difference between time taken by Ravish and Manish alone to do the work = E = 5x – 3x = 2x

E = 16