# Quantitative Aptitude DI - **Nov 07 2020**

Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.

**Study the following information carefully and answer the questions given below.**

The bar chart given below shows the percentage of quantity of wine, soda and water in tank A, tank B, tank C and tank D and line chart given below shown the capacity of the tank A, tank B, tank C and tank D. Study the data carefully and answer the following questions. (Note- all the tanks are filled to its full capacity)

**1) If 20% of the quantity of tank A and 30% of the quantity of tank B are mixed in tank E. Find the amount of water in tank E.**

**A**.34.4 litres

**B**.32.4 litres

**C**.31.4 litres

**D**.31.6 litres

**E**.30.4 litres

**2) If any three tanks are mixed in a large tank then the maximum quantity of wine can be obtained from which combination?**

**A**. Tank A + Tank B + Tank C

**B**. Tank A + Tank B + Tank D

**C**. Tank A + Tank C + Tank D

**D**. Tank B + Tank C + Tank D

**E**. Both option c and d are correct.

**3) Find the ratio of the quantity of wine, soda and water respectively in a glass if the 40ml liquid is taken from tank C and 60 ml liquid is tank from tank D.**

**A**.33: 37: 30

**B**.30: 37: 33

**C**.37: 33: 30

**D**.40: 33: 27

**E**.33: 47: 20

**4) If the price of wine is Rs. 600/litre and price of soda is Rs. 80/litre. Find the amount of profit obtained by selling the whole mixture of tank C at the rate of Rs. 500/litre.**

**A**.Rs. 44000

**B**.Rs. 54000

**C**.Rs. 34000

**D**.Rs. 36000

**E**.Rs. 64000

**5) The total quantity of soda in all the tanks is approximately what percent of the total quantity of wine in all the tanks?**

**A**.110%

**B**.125%

**C**.120%

**D**.130%

**E**.135%

**Answers :**

**1) Answer: E**

**Tank A**

20% of 160 = 32 litres

Quantity of water = 50% of 32 = 16 litres

**Tank B**

30% of 120 = 36 litres

Quantity of water = 40% of 36 = 14.4 litres

Quantity of water in tank E = 16 litres + 14.4 litres = 30.4 litres

**2) Answer: C**

Quantity of wine

**Option a)** = 20% of 160 + 25% of 120 + 30% of 180

= 32+ 30+ 54

=116 litres

**Option b)** 20% of 160 + 25% of 120 + 35% of 150

= 32+30 + 52.5

= 114.5 litres

**Option c)** 20% of 160+ 30% of 180+ 35% of 150

= 32+ 54+ 52.5

= 138.5 litres (answer)

**Option d)** = 25% of 120 + 30% of 180+35% of 150

= 30+ 54+ 52.5

= 136.5 litres

**3) Answer: A**

**Tank C**

=wine (30% of 40ml) + soda (25% of 40 ml) + water (45% of 40ml)

40ml = wine (12ml) + soda (10ml) + water (18ml)

**Tank D**

= wine (35% of 60ml) + soda (45% of 60ml) + water (20% of 60ml)

60ml = wine (21ml) + soda (27 ml) + water (12ml)

**Glass**

Wine (12ml+21ml) + soda (10ml+27ml) + water (18ml+12ml)

Wine (33ml) + soda (37ml) + water (30ml)

Required ratio = 33: 37: 30

**4) Answer: B**

Selling price of tank C liquid = 180 * 500 = Rs. 90000

Cost price of tank C liquid = cost of wine + cost of soda

Cost price of tank C liquid = quantity of wine * 600 + quantity of soda * 80

Cost price of tank C liquid = (30% of 180) * 600 + (25% of 180) * 80

Cost price of tank C liquid = 54 * 600 + 45 * 80

Cost price of tank C liquid = 32400 + 3600

Cost price of tank C liquid = 36000

Required profit = 90000 - 36000 = Rs. 54000

**5) Answer: C**

** **Quantity of soda = 30% of 160 + 35% of 120 + 25% of 180 + 45% of 150

= 48+ 42+45+ 67.5

= 202.5

Quantity of wine = 20% of 160 + 25% of 120 + 30% of 180+ 35% of 150

= 32 + 30 + 54 + 52.5

= 168.5

Required %age = (202.5/168.5)*100 = 120%