Quantitative Aptitude DI
Nov 07 2020
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
Study the following information carefully and answer the questions given below.
The bar chart given below shows the percentage of quantity of wine, soda and water in tank A, tank B, tank C and tank D and line chart given below shown the capacity of the tank A, tank B, tank C and tank D. Study the data carefully and answer the following questions. (Note- all the tanks are filled to its full capacity)
1) If 20% of the quantity of tank A and 30% of the quantity of tank B are mixed in tank E. Find the amount of water in tank E.
A.34.4 litres
B.32.4 litres
C.31.4 litres
D.31.6 litres
E.30.4 litres
2) If any three tanks are mixed in a large tank then the maximum quantity of wine can be obtained from which combination?
A. Tank A + Tank B + Tank C
B. Tank A + Tank B + Tank D
C. Tank A + Tank C + Tank D
D. Tank B + Tank C + Tank D
E. Both option c and d are correct.
3) Find the ratio of the quantity of wine, soda and water respectively in a glass if the 40ml liquid is taken from tank C and 60 ml liquid is tank from tank D.
A.33: 37: 30
B.30: 37: 33
C.37: 33: 30
D.40: 33: 27
E.33: 47: 20
4) If the price of wine is Rs. 600/litre and price of soda is Rs. 80/litre. Find the amount of profit obtained by selling the whole mixture of tank C at the rate of Rs. 500/litre.
A.Rs. 44000
B.Rs. 54000
C.Rs. 34000
D.Rs. 36000
E.Rs. 64000
5) The total quantity of soda in all the tanks is approximately what percent of the total quantity of wine in all the tanks?
A.110%
B.125%
C.120%
D.130%
E.135%
Answers :
1) Answer: E
Tank A
20% of 160 = 32 litres
Quantity of water = 50% of 32 = 16 litres
Tank B
30% of 120 = 36 litres
Quantity of water = 40% of 36 = 14.4 litres
Quantity of water in tank E = 16 litres + 14.4 litres = 30.4 litres
2) Answer: C
Quantity of wine
Option a) = 20% of 160 + 25% of 120 + 30% of 180
= 32+ 30+ 54
=116 litres
Option b) 20% of 160 + 25% of 120 + 35% of 150
= 32+30 + 52.5
= 114.5 litres
Option c) 20% of 160+ 30% of 180+ 35% of 150
= 32+ 54+ 52.5
= 138.5 litres (answer)
Option d) = 25% of 120 + 30% of 180+35% of 150
= 30+ 54+ 52.5
= 136.5 litres
3) Answer: A
Tank C
=wine (30% of 40ml) + soda (25% of 40 ml) + water (45% of 40ml)
40ml = wine (12ml) + soda (10ml) + water (18ml)
Tank D
= wine (35% of 60ml) + soda (45% of 60ml) + water (20% of 60ml)
60ml = wine (21ml) + soda (27 ml) + water (12ml)
Glass
Wine (12ml+21ml) + soda (10ml+27ml) + water (18ml+12ml)
Wine (33ml) + soda (37ml) + water (30ml)
Required ratio = 33: 37: 30
4) Answer: B
Selling price of tank C liquid = 180 * 500 = Rs. 90000
Cost price of tank C liquid = cost of wine + cost of soda
Cost price of tank C liquid = quantity of wine * 600 + quantity of soda * 80
Cost price of tank C liquid = (30% of 180) * 600 + (25% of 180) * 80
Cost price of tank C liquid = 54 * 600 + 45 * 80
Cost price of tank C liquid = 32400 + 3600
Cost price of tank C liquid = 36000
Required profit = 90000 - 36000 = Rs. 54000
5) Answer: C
Quantity of soda = 30% of 160 + 35% of 120 + 25% of 180 + 45% of 150
= 48+ 42+45+ 67.5
= 202.5
Quantity of wine = 20% of 160 + 25% of 120 + 30% of 180+ 35% of 150
= 32 + 30 + 54 + 52.5
= 168.5
Required %age = (202.5/168.5)*100 = 120%