Study the following data carefully and answer the questions:

The line chart given below shows number of rides taken by two types of drivers A and B in five given months:

Number of rides taken = Number of rides received – Number of rides accepted

Table shows percentage of rides taken by female passengers.

1) What is the difference betweentotal female rides taken by A in Jan and Feb together and total female rides taken by B in Feb and May together?

a) 10

b) 8

c) 16

d) 12

e) None of these

2) What is the ratio of average of female rides taken by A on Feb and April together to the average of female rides taken by B on Feb, March and May together?

a) 26: 25

b) 37: 36

c) 17: 16

d) 9: 8

e) None of these

3) If ratio of male rides taken by A to that by B on March is 3: 2, then what percent of total rides by A on March are taken by female passengers?

a) 60%

b) 80%

c) 75%

d) 70%

e) None of these

4) If average of number of male rides taken by driver A on all the five months is 136, then female rides taken by driver A on March is what percent more than the female rides taken by driver B on that month?

a) 160%

b) 90%

c) 110%

d) 120%

e) None of these

5) If out of total received by B on Jen, Feb and March, 80%, 84% and 64% respectively are taken, then what is the average number of rides received by B on those three months?

a) 350

b) 400

c) 450

d) 300

e) None of these

Answers :

1) Answer: D

Total female rides taken by A in Jan and Feb together = 88 + 144 = 232

Total female rides taken by B in Feb and May together = 84 + 160 = 244

Required difference = 244 – 232 = 12

2) Answer: B

Average of female rides taken by A on Feb and April together = (144 + 78)/2 = 111

Average of female rides taken by B on Feb, March and May together = (84 + 80 + 160)/3 = 108

Required ratio = 111: 108 = 37: 36

3) Answer: A

Male rides taken by B on March = 160 – 80 = 80

Male rides taken by A on March = 80 * (3/2) = 120

Female rides taken by A on March = 300 – 120 = 180

Required percent = (180/300) * 100 = 60%

4) Answer: C

Total number of male rides taken by driver A on all the five months = 136 * 5 = 680

Male rides taken by driver A on March = 680 – (88 + 144 + 78 + 238) = 132

Female rides taken by driver A on March = 300 – 132 = 168

Required percent = [(168 – 80)/80] * 100 = 110%

5) Answer: B

Total rides received by B om Jan = 360 * (100/80) = 450

Total rides received by B om Feb = 420 * (100/84) = 500

Total rides received by B om March = 160 * (100/64) = 250

Required average = (450 + 500 + 250)/3 = 400