Quantitative Aptitude DI
Oct 16 2020
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
Direction (1-5): Study the following data carefully and answer the questions:
A good train started with station A with some goods loaded in the train. It passed through stations B, C, D, E and reaches at station F. Some goods from the train is de-loaded from train at stations B, C, D, E and F. Station F is not destination station of the train, it goes after station F with remaining good in it.
Funnel chart given below shows the amount of goods de-loaded at five different stations.
Note 1: Remaining quantity of goods in the train when it reaches to station D is 350 kg.
Note 2: Speed of train when at starts from station A is 40 km/h and its speed increased by 0.2 km/h after de-loading of every 1 kg of goods.
1) The speed of train when it leaves station C is how much percentage increased the speed when it leaves station A?
a) 90%
b) 75%
c) 65%
d) 45%
e) 50%
2) What is the ratio of sum of total quantity of goods de-loaded at stations D, E and F together to the total quantity of goods loaded at station A?
a) 18: 23
b) 17: 24
c) 15: 22
d) 11: 19
e) 6: 13
3) What is the difference between total quantity of goods de-loaded at stations B, C and Dtogether and total quantity of goods de-loaded at stations E and F together?
a) 60 kg
b) 20 kg
c) 45 kg
d) 30 kg
e) 40 kg
4) If at station D, 144 kg more goods de-loaded, then new speed of train when it leaves station D will be what percent of its original speed when it leaves that station?
a) 132%
b) 128%
c) 164%
d) 120%
e) 108%
5) What is the average of total quantity of goods de-loaded at four stations B, C, E and F together?
a) 80 kg
b) 87.5 kg
c) 82.5 kg
d) 72.5 kg
e) 67.5 kg
Answers:
Directions (Q. 6 - 10):
Total loaded at station A = ‘a’ kg
Goods de-loaded at station B = 1/6 of a = a/6
Remaining goods = a - (a/6) = 5a/6
Goods de-loaded at station C = 12.5% of 5a/6 = 5a/48
Remaining goods = a - (a/6) - (5a/48) = 350
(48a - 8a - 5a) / 48 =350
a = 480
Total quantity of goods loaded at station A = a = 480 kg
Goods de-loaded at station B = a/6 = 80 kg
Goods de-loaded at station C = 5a/48 = 50 kg
Goods de-loaded at station D = ‘x’ kg
Goods de-loaded at station E = ‘x + 40’ kg
Goods de-loaded at station F = 50 + 10 = 60 kg
Remaining goods when left station F = 350 – x – (x + 40) – 60 = 10
2x = 240
x = 120
Goods de-loaded at station D = x = 120 kg
Goods de-loaded at station E = x + 40 = 160 kg
Table given below shows the quantity of goods de-loaded from train and speed of train when it leaves a station after de-loading the goods:
1) Answer: C
Speed of train when it leaves station A = 40 km/h
Speed of train when it leaves station C = 66 km/h
Difference = 66 – 40 = 26 km/h
Required percent = (6/40) * 100
= 65%
2) Answer: B
Total quantity of goods de-loaded at stations D, E and F together
= 120 + 160 + 60 = 340 kg
Total quantity of goods loaded at station A = 480 kg
Required ratio = 340: 480 = 17: 24
3) Answer: D
Total quantity of goods de-loaded at stations B, C and D together
= 80 + 50 + 120 = 250 kg
Total quantity of goods de-loaded at stations E and F together
= 160 + 60 = 220 kg
Required difference = 250 – 220 = 30 kg
4) Answer: A
Since, 144 kg more goods de-loaded.
Increment in the speed of train when it leaves station D = (0.2 * 144) = 28.8 km/h
New speed of train when it leaves station D = 90 + 28.8 = 118.8 km/h
Required percent = (118.8/9) * 100
= 132%
5) Answer: B
Total quantity of goods de-loaded at stations B, C, E and F together
= 80 + 50 + 160 + 60 = 350 kg
Required average = 350/4 = 87.5 kg