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Quantitative Aptitude DI

Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.

Study the following information carefully and answer the given questions?

The line graph shows the number of students in three different classes (A, B and C).

A teacher distributes five different stationary items viz. Note, Pen, Book, Pencil and Bag in each class for each student.

In class A, teacher distributes 3 notes, 1 pen, 5 books, x pencil and (x – 1) bag for each student. Total item distributed in the class A is 480.

In class B, teacher distributes 4 notes, y pens, (y + 4) books, (x + 1) pencils and (y – 1) bags for each student. Total items distributed in the class B is twice the total item distributed in the class A.

In class C, total notes distributed by teacher is 10 notes more than total notes distributed in class B and the ratio of total books distributed in class A to C is 2: 3. And then distributes (y + 1) pens, x pencils and z bags for each student.

The teacher distributed a total of 2290 stationary items to all the classes.

1) Quantity I: Find the average number of items distributed in class A

Quantity II: Find the average number of items distributed in class B

a) Quantity I < Quantity II

b) Quantity I = Quantity II

c) Quantity I ≥ Quantity II

d) Quantity I ≤ Quantity II

e) Quantity I > Quantity II

2) What is the ratio of the total pencil to total bags distributed for all the schools together?

a) 7: 9

b) 8: 11

c) 12: 5

d) 6: 7

e) 5: 4

3) Total pen and pencil distributed for school B together is what percentage more/less than the total note and pen distributed in class C together?

a) 20% more

b) 20% less

c) 40% less

d) 25% less

e) 25% more

4) Which of the following stationary items distributed maximum for all the class together?

a) Pen

b) Note

c) Books

d) Pencil

e) Bag

5) What is the difference between the number of Note, pen and bags distributed for all the class together to that of the remaining items distributed for all the class together?

a) 130

b) 180

c) 190

d) 110

e) None of these

Answers :

Directions (6 – 10):

Class A:

Total notes = 3 * 40 = 120

Total pens = 40 * 1 = 40

Total books = 40 * 5 = 200

Total pencils = 40 * x

Total bags = 40 * (x – 1)

Total item = 120 + 40 + 200 + 40x + 40 (x – 1) = 480

80x – 40 = 120

= > 80x = 160 = > x = 2

Total pencils = 40 * x = 80

Total bags = 40 * (x – 1) = 40

Class B:

Total notes = 60 * 4 = 240

Total pens = 60 * y

Total books = 60 * (y + 4)

Total pencils = 60 * (x + 1) = 60 * (2 + 1) = 180

Total bags = 60 * (y – 1)

Total items = 480 * 2 = 960

240 + 60y + 60y + 240 + 180 + 60y – 60 = 960

600 + 180y = 960

= > y = 360/180 = 2

Total pens = 60 * y = 120

Total books = 60 * (y + 4) = 360

Total bags = 60 * (y – 1) = 60

Class C:

Total notes = 240 + 10 = 250

Total books = 200/2 * 3 = 300

Total pens = 50 * (y + 1) = 50 * (2 + 1) = 150

Total pencils = 50 * x = 50x = 50 * 2 = 100

Total bags = 50 * z

Total items = 2290 – 480 – 960 = 850

250 + 300 + 150 + 100 + 50z = 850

50z = 50

= > z = 1

Total bags = 50 * 1 = 50

1) Answer: A

Quantity I:

Required average = 480/40 = 12

Quantity II:

Required average = 960/60 = 16

Hence, Quantity I < Quantity II

2) Answer: C

Required ratio = 360: 150 = 12: 5

3) Answer: D

Required percentage

= [(250 + 150) – (120 + 180)]/(150 + 250) * 100

= 100/400 * 100 = 25% less

4) Answer: C

Note = 610

Pen = 310

Books = 860

Pencil = 360

Bag = 150

5) Answer: E

Total Note, pen and bags distributed for all the class together

= (610 + 310 + 150) = 1070

Remaining items = 2290 – 1070 = 1220

Required difference = 1220 – 1070 = 150