Quantitative Aptitude DI
Oct 17 2020
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
Study the following information carefully and answer the given questions?
The line graph shows the number of students in three different classes (A, B and C).
A teacher distributes five different stationary items viz. Note, Pen, Book, Pencil and Bag in each class for each student.
In class A, teacher distributes 3 notes, 1 pen, 5 books, x pencil and (x – 1) bag for each student. Total item distributed in the class A is 480.
In class B, teacher distributes 4 notes, y pens, (y + 4) books, (x + 1) pencils and (y – 1) bags for each student. Total items distributed in the class B is twice the total item distributed in the class A.
In class C, total notes distributed by teacher is 10 notes more than total notes distributed in class B and the ratio of total books distributed in class A to C is 2: 3. And then distributes (y + 1) pens, x pencils and z bags for each student.
The teacher distributed a total of 2290 stationary items to all the classes.
1) Quantity I: Find the average number of items distributed in class A
Quantity II: Find the average number of items distributed in class B
a) Quantity I < Quantity II
b) Quantity I = Quantity II
c) Quantity I ≥ Quantity II
d) Quantity I ≤ Quantity II
e) Quantity I > Quantity II
2) What is the ratio of the total pencil to total bags distributed for all the schools together?
a) 7: 9
b) 8: 11
c) 12: 5
d) 6: 7
e) 5: 4
3) Total pen and pencil distributed for school B together is what percentage more/less than the total note and pen distributed in class C together?
a) 20% more
b) 20% less
c) 40% less
d) 25% less
e) 25% more
4) Which of the following stationary items distributed maximum for all the class together?
a) Pen
b) Note
c) Books
d) Pencil
e) Bag
5) What is the difference between the number of Note, pen and bags distributed for all the class together to that of the remaining items distributed for all the class together?
a) 130
b) 180
c) 190
d) 110
e) None of these
Answers :
Directions (6 – 10):
Class A:
Total notes = 3 * 40 = 120
Total pens = 40 * 1 = 40
Total books = 40 * 5 = 200
Total pencils = 40 * x
Total bags = 40 * (x – 1)
Total item = 120 + 40 + 200 + 40x + 40 (x – 1) = 480
80x – 40 = 120
= > 80x = 160 = > x = 2
Total pencils = 40 * x = 80
Total bags = 40 * (x – 1) = 40
Class B:
Total notes = 60 * 4 = 240
Total pens = 60 * y
Total books = 60 * (y + 4)
Total pencils = 60 * (x + 1) = 60 * (2 + 1) = 180
Total bags = 60 * (y – 1)
Total items = 480 * 2 = 960
240 + 60y + 60y + 240 + 180 + 60y – 60 = 960
600 + 180y = 960
= > y = 360/180 = 2
Total pens = 60 * y = 120
Total books = 60 * (y + 4) = 360
Total bags = 60 * (y – 1) = 60
Class C:
Total notes = 240 + 10 = 250
Total books = 200/2 * 3 = 300
Total pens = 50 * (y + 1) = 50 * (2 + 1) = 150
Total pencils = 50 * x = 50x = 50 * 2 = 100
Total bags = 50 * z
Total items = 2290 – 480 – 960 = 850
250 + 300 + 150 + 100 + 50z = 850
50z = 50
= > z = 1
Total bags = 50 * 1 = 50
1) Answer: A
Quantity I:
Required average = 480/40 = 12
Quantity II:
Required average = 960/60 = 16
Hence, Quantity I < Quantity II
2) Answer: C
Required ratio = 360: 150 = 12: 5
3) Answer: D
Required percentage
= [(250 + 150) – (120 + 180)]/(150 + 250) * 100
= 100/400 * 100 = 25% less
4) Answer: C
Note = 610
Pen = 310
Books = 860
Pencil = 360
Bag = 150
5) Answer: E
Total Note, pen and bags distributed for all the class together
= (610 + 310 + 150) = 1070
Remaining items = 2290 – 1070 = 1220
Required difference = 1220 – 1070 = 150