Quantitative Aptitude DI
Sep 25 2020
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
Direction (1-5): Study the following data carefully and answer the questions:
Information given below shows the method by which electricity bill is generated. There are two bars: Domestic and Commercial and parameters to calculate the bill is different for both the bars.
For both bars there are three ranges A, B and C and table given below shows the fixed charge (rupees) and per unit charge (rupees) of those three ranges for the two bars:
Formula to calculate electricity bill is given below:
Net amount = Fixed charges + Energy charges + Electricity Duty – Rebate
Energy charges = Charges units (KW) * Per unit charge
Rebate = 10% of fixed charge + 25% of energy charges
1) What is the difference between monthly electricity bill for a family (domestic) and for a shopkeeper (commercial) if the average consumption per day of electricity in the family is 3 KW while average consumption per day of electricity in the shop is 4KW? The connection range for family and shop is B and A respectively and monthly electricity duty fee for family and shop is Rs.600 and Rs.500 respectively.
a) Rs.100
b) Rs.80
c) Rs.120
d) Rs.125
e) None of these
2) If in January, connection range of a family (domestic) is A while in February, it becomes in range B. Electricity duty fee and average consumption per day of electricity of the family for both the months is Rs.450 and 2 KW respectively, then what will be the ratio of monthly electricity bill amount of the family in January to that in February?
a) 11: 17
b) 5: 9
c) 19: 26
d) 21: 28
e) None of these
3) A family (domestic) comes under range C of the connection and total monthly electricity bill amount paid by the family is Rs.2400 while average consumption per day of electricity in the family is 5 KW, then what is the electricity duty fee of the family in that month?
a) Rs.625
b) Rs.750
c) Rs.455
d) Rs.555
e) None of these
4) A business (commercial) comes under connection range C and electricity duty fee of the business is Rs.325. If the total monthly electricity bill amount paid by the business is Rs.2800, then what is the average consumption per day of electricity in that business?
a) 4 KW
b) 2 KW
c) 3 KW
d) 5 KW
e) None of these
5) If there are two shops P and Q (both commercial), P comes under connection range A while Q comes under connection range B. If average consumption per day of both the shops is 2.5 KW and electricity duty fee for the shops is Rs.497.5, then monthly electricity bill for shop P is approximately what per cent of monthly electricity bill for shop Q?
a) 62.5%
b) 71.5%
c) 57.5%
d) 48.5%
e) None of these
Answers :
1) Answer: A
For family:
Energy charges = (30 * 3) * 8 = Rs.720
Rebate = 10% of 400 + 25% of 720 = 40 + 180 = Rs.220
Net bill amount = 400 + 720 + 600 – 220 = Rs.1500
For shop:
Energy charges = (30 * 4) * 7.5 = Rs.900
Rebate = 10% of 250 + 25% of 900 = 25 + 225 = Rs.250
Net bill amount = 250 + 900 + 500 – 250 = Rs.1400
Required difference = 1500 – 1400 = Rs.100
2) Answer: C
In January:
Energy charges = (30 * 2) * 5 = Rs.300
Rebate = 10% of 200 + 25% of 300 = 20 + 75 = Rs.95
Net bill amount = 200 + 300 + 450 – 95 = Rs.855
In February:
Energy charges = (30 * 2) * 8 = Rs.480
Rebate = 10% of 400 + 25% of 480 = 40 + 120 = Rs.160
Net bill amount = 400 + 480 + 450 – 160 = Rs.1170
Required ratio = 855: 1170 = 19: 26
3) Answer: D
Let electricity duty fee = ‘x’
Fixed charges = Rs.800
Energy charges = (30 * 5) * 10 = Rs.1500
Rebate = 10% of 800 + 25% of 1500 = 80 + 375 = Rs.455
Net bill amount = 800 + 1500 + x – 455 = 2400
1845 + x = 2400
x = 555
Hence, electricity duty fee = Rs.555
4) Answer: A
Fixed charges = Rs.1250
Let average consumption per day of electricity = x
Energy charges = (30 * x) * 15 = 450x
Rebate = 10% of 1250 + 25% of 450x = (125 + 112.5x)
Net bill amount = 1250 + 450x + 325 – (125 + 112.5x) = 2800
1450 + 337.5x = 2800
337.5x = 1350
x = 4
Hence, average consumption of electricity per day = 4 KW
5) Answer: B
For shop P:
Energy charges = (30 * 2.5) * 7.5 = Rs.562.5
Rebate = 10% of 250 + 25% of 562.5 = 25 + 140.625 = Rs.165.625
Net bill amount = 250 + 562.5 + 497.5 – 165.625 = Rs.1144.375
For shop Q:
Energy charges = (30 * 2.5) * 10 = Rs.750
Rebate = 10% of 600 + 25% of 750 = 60 + 187.5 = Rs.247.5
Net bill amount = 600 + 750 + 497.5 – 247.5 = Rs.1600
Required per cent = (1144.375/1600) * 100 = 71.5%