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Quantitative Aptitude DI - Sep 08 2020

Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.

Data Interpretation (Formula Based)

Study the information carefully and answer the questions.

The line graph given below shows the population Density (per square km) of five towns A, B, C, D and E as per 2001 census.

The line graph given below shows the Land Area (per square km) of five towns A, B, C, D and E as per 2001 census.

 

1) If the difference between male and female population of town C is 18400 (male population being greater than female population), then what is the approximate gender ratio of town R?

a) 137%

b) 127%

c) 141%

d) 131%

e) None of these

2) The gender ratio of town D is 66more than the gender ratio of town E and the male population often D is 25600  more than the male population of town E. What is the ratio of female population of town E to the female population of town D?

a) 3:2

b) 3:1

c) 2:3

d) 1:3

e) None of these

3) The total population of town D is approximately what percent more or less than the total population of town C?

a) 53%

b) 48%

c) 51%

d) 55%

e) None of these

4) The gender ratio of town A is 15 more than the gender ratio of town B. if it is mentioned that the female population of town B is twice the female population of town A, then find the male population of town A?  

a) 20200

b) 19200

c) 18200

d) Can’t be determined

e) None of these

5) What is the ratio of the sum of population of town B and C together to the sum of population of town E and A together?

a) 135:117

b) 123:107

c) 125:127

d) 133:125

e) None of these

Answers :

1) Answer: A

Let the female population of town C be F.

Male population of town C = F + 18400

Total Population = 2800 x 42 = 117600

Now, F +F +18400 = 117600

F = 49600

So, male population = 49600 + 18400 = 68000

= 137.09 = 137 % (approx)

2) Answer: D

Population of town D = 48 x 1200 = 57600

Population of town E = 64 x 2000 = 12800

Let male population of town E be M.

Male population of town D = M + 25600

Female population of town E = 12800 –M

Female population of town D  = 57600 –M -25600 = 32000 – M

According to question,

We get M = 3200

Female population of town E = 12800 – 3200 = 9600

Female population of town D = 32000 – 3200 = 28800

Required ratio = 9600 : 28800

= 1:3

3) Answer: C

Population of town C = 42 x 2800 = 117600

Population of town D = 1200 x 48 = 57600

= 51.02 = 51%

4) Answer: B

Let F be female population of town A.

2F = female population of town B.

Total population of A = 1800 x 24 = 43200

Total population of B = 2200 x 36 = 79200

Male population of A = 43200 – F

Male population of B = 79200 – 2F

According to question,

F = 24000

Thus Male population of town A = 43200 – 24000 = 19200 

5) Answer: B

Population of town A = 24 x 1800 = 43200

Population of town B = 22 x 3600 = 79200

Population of town C = 42 x 2800 = 117600

Population of town E = 64 x 2000 = 128000

Required Ratio

(79200 + 117600) : (128000 + 43200)

196800:171200

123:107