# Quantitative Aptitude DI - **Sep 08 2020**

Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.

**Data Interpretation (Formula Based)**

**Study the information carefully and answer the questions.**

**The line graph given below shows the population Density (per square km) of five towns A, B, C, D and E as per 2001 census.**

**The line graph given below shows the Land Area (per square km) of five towns A, B, C, D and E as per 2001 census.**

**1) If the difference between male and female population of town C is 18400 (male population being greater than female population), then what is the approximate gender ratio of town R?**

a) 137%

b) 127%

c) 141%

d) 131%

e) None of these

**2) The gender ratio of town D is 66****more than the gender ratio of town E and the male population often D is 25600 more than the male population of town E. What is the ratio of female population of town E to the female population of town D?**

a) 3:2

b) 3:1

c) 2:3

d) 1:3

e) None of these

**3) The total population of town D is approximately what percent more or less than the total population of town C?**

a) 53%

b) 48%

c) 51%

d) 55%

e) None of these

**4) The gender ratio of town A is 15 more than the gender ratio of town B. if it is mentioned that the female population of town B is twice the female population of town A, then find the male population of town A?**

a) 20200

b) 19200

c) 18200

d) Can’t be determined

e) None of these

**5) What is the ratio of the sum of population of town B and C together to the sum of population of town E and A together?**

a) 135:117

b) 123:107

c) 125:127

d) 133:125

e) None of these

**Answers :**

**1) Answer: A**

Let the female population of town C be F.

Male population of town C = F + 18400

Total Population = 2800 x 42 = 117600

Now, F +F +18400 = 117600

F = 49600

So, male population = 49600 + 18400 = 68000

= 137.09 = 137 % (approx)

**2) Answer: D**

Population of town D = 48 x 1200 = 57600

Population of town E = 64 x 2000 = 12800

Let male population of town E be M.

Male population of town D = M + 25600

Female population of town E = 12800 –M

Female population of town D = 57600 –M -25600 = 32000 – M

According to question,

We get M = 3200

Female population of town E = 12800 – 3200 = 9600

Female population of town D = 32000 – 3200 = 28800

Required ratio = 9600 : 28800

= 1:3

**3) Answer: C**

Population of town C = 42 x 2800 = 117600

Population of town D = 1200 x 48 = 57600

= 51.02 = 51%

**4) Answer: B**

Let F be female population of town A.

2F = female population of town B.

Total population of A = 1800 x 24 = 43200

Total population of B = 2200 x 36 = 79200

Male population of A = 43200 – F

Male population of B = 79200 – 2F

According to question,

F = 24000

Thus Male population of town A = 43200 – 24000 = 19200** **

**5) Answer: B**

Population of town A = 24 x 1800 = 43200

Population of town B = 22 x 3600 = 79200

Population of town C = 42 x 2800 = 117600

Population of town E = 64 x 2000 = 128000

Required Ratio

(79200 + 117600) : (128000 + 43200)

196800:171200

123:107